Respuesta :
Answer:
= 6.848 × 10^-24 J
Explanation:
Energy of a photon may be given by the Formula;
E = hf or E = hc/λ where E is the c is the speed of light, h is the planks constant and λ is the wavelength.
The speed of light is 3 × 10^8 m/s, h is 6.626 × 10^-34 Js
Hence;
E = (6.62 × 10^-34 Js × 3× 10^8 m/s)/ 2.9 × 10^-2 m
=6.848 × 10^-24 Joules
The energy carried by a single photon is referred to as photon energy. Energy per photon of such radiation will be 6.848×10⁻²⁴J.
What is the energy of a photon?
The energy carried by a single photon is referred to as photon energy. The photon's electromagnetic frequency is directly proportional to the amount of energy it contains,
The wavelength is inversely proportionate. The greater the frequency of a photon, the more energy it has.
The given data in the problem will be;
λ is the wavelength of infrared radiation=29 nM=29×10⁻⁹m
c is the speed of light=3×10⁸ m/sec
E is the energy of photons=?
h is the plank constant=6.6×10⁻³⁴
The formula for the energy of photons is;
[tex]\rm E=\frac{hc}{\lambda} \\\\ \rm E=\frac{6.6 \times 10^{-34}\times 3\times 10^}{2.9\times10^{-2}} \\\\\rm E=6.848 \times 10^{-24}\ J[/tex]
Hence the energy per photon of such radiation is 6.848×10⁻²⁴ J.
To learn more about the energy of photons refer to the link;
https://brainly.com/question/19795551
