Answer:
[tex]\large\boxed{(g\circ f)(5)=16}[/tex]
Step-by-step explanation:
[tex]f(x)=2x-8\\\\g(x)=x^4\\\\(g\circ f)(x)\to\text{substitute (2x - 8) to the function}\ g(x):\\\\(g\circ f)(x)=(2x-8)^4\\\\(g\circ f)(5)\to\text{put x = 5:}\\\\(g\circ f)(5)=(2\cdot5-8)^4=(10-8)^4=(2)^4=16[/tex]
