Which is the equation of a line that has a slope of -2/3 and passes through point (–3, –1)?

Answer:
y = (-2/3)x-3
Step-by-step explanation:
Hello:
equation is the line is : y = ax+b a is a slope
y = (-2/3)x+b
passing through the point (−3;−1) : -1 =(-2/3)(-3)+b so : b = -3
y = (-2/3)x-3
second solution : you can verify (-3 ; -1) in the equation : y = (-2/3)x-3