Answer:
Al₂O₃
Explanation:
Given 1.132 g Al and 1.174 O,
Number of moles of Al = mass of Al * 1 mole of Al/ molar mass of Al
Molar mass of Al = 26.98 g/mol
∴ number of moles of Al = 1.32 * 1/26.98 = 0.04892 moles
Number of moles of O = mass of O * 1 mole of O/ molar mass of O
Molar mass of O = 16g/mol
Number of moles of O = 1.174* 1/16 = 0.073375 moles
Aluminium / Oxygen = 0.04892/0.073375 = 0.6667 = 2/3
So, 2 moles of Al with 3 moles of O will be required
