Answer:
Part A) The zero's of the function are [tex]x=0.84, x=7.16[/tex]
Part B) The solution set is the interval [tex][0.84,7.16][/tex]
Step-by-step explanation:
we have
[tex]x^2-8x+6\le0[/tex]
Using a graphing calculator
Part A) What are the zeros of the inequality to the nearest hundredth?
The zero's of the function are the values of x when the values of the function are equal to zero
see the attached figure
The zero's of the function are
[tex]x=0.84, x=7.16[/tex]
Part B) What is the solution set for the inequality?
The solution set is the interval [tex][0.84,7.16][/tex]
All real numbers greater than or equal to 0.84 and less than or equal to 7.16
[tex]0.84\leq x \leq 7.16[/tex]