Respuesta :
Answer:
So the sequence will be 4, 8, 16, 32, 64, 128 .......
Step-by-step explanation:
We have to graph the first six terms of a sequence with first term a = 4 and r = 2 Since r denotes common ratio so the given sequence is a geometric sequence.
Now we know the explicit formula for a geometric sequence is
[tex]T_{(n)}=a(r)^{n-1}[/tex]
Since [tex]T_{1}[/tex] = 4
So [tex]T_{2}=4(2)^{2-1}[/tex] = 4 × 2 = 8
[tex]T_{3}=4(2)^{3-1}[/tex] = 4 × 2² = 4 × 4 = 16
[tex]T_{4}=4(2)^{4-1}[/tex] = [tex](4)(2)^{3}[/tex] = 4 × 8 = 32
[tex]T_{5}=4(2)^{5-1}[/tex] = [tex]4(2)^{4}[/tex] = 4 × 16 = 64
[tex]T_{6}=4(2)^{6-1}[/tex] = [tex]4(2)^{5}[/tex] = 4 × 32 = 128
So the sequence will be 4, 8, 16, 32, 64, 128 .......
