Respuesta :
Answer:
38,674.This area represents the increase in population over a 10-year period.
Step-by-step explanation:
When graphed over the interval 0 ≤ t ≤ 10, the birth rate is more than the death rate. This means the area between the two curves is the amount of births subtract the amount of deaths. This results in an area which means the increase of the population.
The birth rate is graphed in green and the death rate is graphed in blue.
To find the area, take the integral of the difference of the functions:
[tex]\int\limits^{10}_0 {2300e^{0.021t} - 1450e^{0.018t} } \, dt \\\\\frac{2300e^{0.021t}}{0.021} - \frac{1450e^{0.018t}}{0.018} \\\\(\frac{2300e^{0.21}}{0.021} -\frac{1450e^{0.18}}{0.018} ) - (\frac{2300}{0.021}- \frac{1450}{0.018} ) \\\\135117.12 - 96442.51 \\\\38,674[/tex]

The area between these curves for 0 ≤ t ≤ 10 is 38674.
The area represents the increase in population over a 10-year period
Given
The birth rate of a population is [tex]\rm b(t) = 2300e^{0.021t }[/tex] people per year.
And the death rate is [tex]\rm d(t)= 1450e^{0.018t}[/tex] people per year.
What is integration?
Integration is the reverse of differentiation.
When graphed over the interval 0 ≤ t ≤ 10, the birth rate is more than the death rate.
The area given the difference between the number of births and the number of deaths, which gives the net number of persons added to the population, or the net population increase over the 10 year period.
Therefore,
The area between these curves for 0 ≤ t ≤ 10 is given by subtracting birth rate and death rate.
[tex]\rm Area \ between \ curves = \int\limits^{10}_0 {(Birth \ rate - Death \ rate)} \, dt\\\\\rm Area \ between \ curves = \int\limits^{10}_0(\rm 2300e^{0.021t }-\rm 1450e^{0.018t)}dt\\\\Area \ between \ curves = \left[ \dfrac{ 2300e^{0.021t }}{0.021}-\dfrac{1450e^{0.018t}}{0.0108} \right ]^{10}_0\\\\Area \ between \ curves =1351117.12-96442.51\\\\Area \ between \ curves =38,674[/tex]
Hence, the area between these curves for 0 ≤ t ≤ 10 is 38674.
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