Answer:
The percent of the volume of the cube reduced is [tex]6.4\%[/tex]
Step-by-step explanation:
The length side of the original cube is equal to
[tex]b^{3} =125\ cm{3}\\b=5\ cm[/tex]
The length side of the reduced cube is equal to
[tex]b=5-3=2\ cm[/tex]
The volume of the reduced cube is equal to
[tex]V=2^{3} =8\ cm^{3}[/tex]
To find the percent of the volume of the cube reduced, apply proportion
[tex]\frac{100\%}{125}= \frac{x\%}{8}\\ \\x=8*100/125\\ \\x=6.4\%[/tex]