ANSWER
[tex](2x-3y) (4x-y) = 8 {x}^{2} -14xy + 3 {y}^{2} [/tex]
EXPLANATION
We want to expand (2x-3y) (4x-y)
We use the distributive property to obtain,
[tex](2x-3y) (4x-y) = 2x(4x-y) -3y(4x-y)[/tex]
We expand to get,
[tex](2x-3y) (4x-y) = 8 {x}^{2} -2xy -12xy + 3 {y}^{2} [/tex]
Combine the middle terms to obtain,
[tex](2x-3y) (4x-y) = 8 {x}^{2} -14xy + 3 {y}^{2} [/tex]
