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URGENT!!! TIMED!!!!
Kievan bought a new eraser that came in a cardboard wrapper.

What is the minimum amount of cardboard used for the wrapper?
38cm^2
40cm^2
76cm^2
80cm^2

IT'S NOT 40

URGENT TIMED Kievan bought a new eraser that came in a cardboard wrapper What is the minimum amount of cardboard used for the wrapper 38cm2 40cm2 76cm2 80cm2 IT class=

Respuesta :

luisejr77

Answer: Third option.

Step-by-step explanation:

You need to find the surface area with the formula for calculate the surface area of a rectangular prism:

[tex]SA=2(wl + lh + hw)[/tex]

Where w is the width, l is the length, and h is the height.

You can observe in the figure that:

[tex]l=5cm\\w=4cm\\h=2cm[/tex]

Then, substituting the values into the formula  [tex]SA=2(wl + lh + hw)[/tex], you get that  minimum amount of cardboard used for the wrapper is:

[tex]SA=2[(4cm)(5cm)+(5cm)(2cm)+(2cm)(4cm)]\\SA=76cm^2[/tex]

Answer:

third option

Step-by-step explanation:

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