Answer:
Option C. [tex]288\pi\ ft^{3}[/tex]
Step-by-step explanation:
we know that
The volume of a sphere is equal to
[tex]V=\frac{4}{3} \pi r^{3}[/tex]
we have
[tex]r=6\ ft[/tex]
substitute
[tex]V=\frac{4}{3} \pi (6)^{3}[/tex]
[tex]V=288\pi\ ft^{3}[/tex]
