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ANSWER
[tex] \frac{9}{25} [/tex]
EXPLANATION
The given information is represented on the Venn diagram above, where x represents students who have both cat and dog.
The sum of all the regions should give us 25.
[tex](15 - x) + x + (16 - x) + 3 = 25[/tex]
Group similar terms to obtain;
[tex] - x + x - x = 25 - 15 - 16 - 3[/tex]
Simplify
[tex] - x = - 9[/tex]
[tex]x = 9[/tex]
The probability that a student chosen at random has a cat and a dog is
[tex] = \frac{9}{25} [/tex]

The probability that a student chosen at random has a cat and a dog is; P(cat and dog) = 9/25.
According to the question, the total number of students is; 25.
- 15 of them have a cat
- 16 of them have a dog
- while, 3 of them have neither
The information above are drawn in a Venn diagram in the attached image.
- where, x = number if students who own a cat and a dog.
Consequently, the total number of students who own a cat, a dog, both or neither is as follows;
- 15-x + x + 16-x + 3 = 25.
- -x = 25 - 34
In essence, x = 9
- Therefore, the number of students who own a cat and a dog is 9.
The probability that a student chosen at random has a cat and a dog is therefore;
- P(cat and dog) = 9/25.
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