Answer:
[tex]\frac{13}{5}[/tex]
Step-by-step explanation:
we know that
[tex]csc(\theta)=\frac{1}{sin(\theta)}[/tex]
In this problem
[tex]sin(\theta)=\frac{1.5}{3.9}[/tex]
substitute
[tex]csc(\theta)=\frac{3.9}{1.5}[/tex]
Multiply by 10 both numerator and denominator
[tex]csc(\theta)=\frac{39}{15}[/tex]
Divide by 3 both numerator and denominator
[tex]csc(\theta)=\frac{13}{5}[/tex]
