This rectangular prism is intersected by a plane that contains points D, E, K, and L.




What is the perimeter of the cross section?


Enter your answer in the box. Round only your final answer to the nearest tenth.



m


A rectangular prism with height 5 meters, length 12 meters, and width 4 meters. The vertices are labeled as G, D, H, L, E, F, J, and K.

Respuesta :

The length of diagonal EK is sqrt(5^2 + 4^2) ≈ 6.403m

 

Hence perimeter = 2*(12 + 6.403) → 36.8 m (to the nearest tenth of a metre)

The perimeter of the cross-section is 36.8 m.

Calculations and Parameters:

Given that the length of diagonal EK is

[tex]\sqrt{(5^2 + 4^2) }[/tex]

6.403m

Thus, the perimeter would be

2*(12 + 6.403)

36.8 m.

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