Answer:
2.14 kW, I₂ < I₁
Explanation:
The three resistors are in parallel. The net resistance is:
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/20 + 1/8 + 1/500
1/R = 0.177
R = 5.65
The power is:
P = IV
P = (V/R) V
P = V²/R
P = (110)² / 5.65
P = 2140 W
P = 2.14 kW
For two resistors in parallel, the one with the higher resistance has the smaller current. I₂ < I₁.
