Answer:
There is no oxygen in 4,2 L of chlorine,
Explanation:
However, we can calculate the volume of 4.2 mol of a gas.
You don't give the volume and temperature, so I shall assume the gas is at STP (0 °C and 1 bar).
This looks like a case where we can use the Ideal Gas Law to calculate the volume.
pV = nRT
Data:
p = 1 bar
n = 4.2 mol
R = 0.083 14 bar.L·K⁻¹mol⁻¹
T = 0 °C = 273.15K
Calculations:
1 × V = 4.2 × 0.083 14 × 273.15
V = 95 L
The volume of 4.2 mol of a gas at STP is [tex]\boxed{\textbf{95 L}}[/tex]
