Answer:
5.655 m³/min
Step-by-step explanation:
Halfway from the bottom of the tank, the radius is half that at the top, so is 1 m. That means the surface area of the water at that point is ...
A = πr² = π(1 m)² = π m²
The rate of flow of water into the tank is the product of this area and the rate of change of depth:
flow rate = area × (depth rate of change)
= (π m²) × (1.8 m/min) = 1.8π m³/min
flow rate ≈ 5.655 m³/min
