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A second's pendulum is taken to the moon. What will be the time period of the pendulum at the moon? (Acceleration due to gravity at the surface of the moon is 1/6 on the surface of earth).

Respuesta :

Answer:

4.89 seconds

Explanation:

The time period of a pendulum is given by

[tex]T = 2\pi \sqrt{\frac{l}{g}}[/tex]

For a second pendulum on earth, T = 2 second

[tex]2 = 2\pi \sqrt{\frac{l}{g}}[/tex]     ...... (1)

Now the time period is T when the pendulum is taken to moon and gravity at moon is 1/6 of gravity of earth

[tex]T = 2\pi \sqrt{\frac{l}{\frac{g}{6}}}[/tex]    ...... (2)

Divide equation (2) by equation (1)

[tex]\frac{T}{2} = \sqrt{6}[/tex]

T = 4.89 seconds

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