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8. Factor 12y2 + 5y - 2 completely.
A. (6y - 1)(2y + 2)
B. (4y - 2)(3y + 1)
C. (4y - 1)(3y + 2)
D. (4y + 1)(3y - 2)

Respuesta :

pamster10
C is the correct answer because in order to factor it completely, you need to factor by grouping it
wanda12345678

Answer:

C. (4y -1)(3y+2)

Step-by-step explanation:

12 y^2 + 5 y - 2

12 y^2 + (-3+8) y - 2

12 y^2 - 3y + 8y - 2

3y(4y-1)+2(4y-1)

(4y-1)(3y+2)

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