If you have a 92.0 gram sample of water, then what mass of hydrogen and what mass of oxygen are in the sample? Make sure you answer in “grams” of Hydrogen and “grams” of Oxygen.

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Answer:

[tex]\boxed{\text{10.29 g H and 81.71 g O}}[/tex]

Explanation:

The formula of water is H₂O.

1. Calculate the molar mass of water

2 H = 2 × 1.008 =   2.016 u

1 O = 1 × 16.00  = 16.00   u

                  MM = 18.02    u

2. Mass of hydrogen

\text{Mass of H} = \text{92.0 g water} \times \dfrac{\text{2.016 g H}}{\text{18.02 g water }} = \textbf{10.29 g[tex]\text{Mass of H} = \text{92.0 g water} \times \dfrac{\text{2.016 g H}}{\text{18.02 g water }} = \textbf{10.29 g H}[/tex] H}

3. Mass of 0xygen

[tex]\text{Mass of O} = \text{92.0 g water} \times \dfrac{\text{16.00 g H}}{\text{18.02 g water }} = \textbf{81.71 g O}\\\\\text{The masses are } \boxed{\textbf{10.29 g H and 81.71 g O}}[/tex]