turbongirl10
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Suppose that the pressure of 0.66 L of gas is 424.9 mm Hg when the temperature is 261.2 K. At what temperature is the volume 7.63 L and the pressure 872.15 mm Hg?

Select one:
a. 6200
b. 1.24e4
c. 3010
d. 11.0

Respuesta :

Edufirst

Answer:

  • Option a. 6200 K

Explanation:

1) Data:

  • V₁ = 0.66 liter
  • P₁ = 42.9 mmHg
  • T = 261.2 K

  • T₂ = ?
  • V₂ = 7.63 liter
  • P₂ = 872.15 mmHg

2) Formula:

Combined law of gases:

  • P₁ V₁ / T₁ = P₂ V₂ / T₂

3) Solution:

  • Solve for T₂:

T₂ = P₂ V₂ T₁ / (P₁ V₁)

  • Substitute:

T₂ = 872.15 mmHg × 7.63 liter × 261.2 K / ( 424.9 mmHg × 0.66 liter)

T₂ = 6198 K

  • Rounding to 2 significant figures, that is 6200 K, which is the first choice.
Caley637
I believe it’s a. 6200

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