Answer:
y=3x+3 is slope-intercept form
y-6=3(x-1) is point-slope form
I don't know the form your equation(s) are in. There are other forms.
Step-by-step explanation:
The slope-intercept form a line is y=mx+b where m is the slope and b is the y-intercept.
So the slope of y=3x+2 is 3.
Parallel lines have the same slope. So the slope of the line we are looking for has a slope of 3.
Therefore, our equation his this form y=3x+b.
We need to now find b.
We know a point (x,y) on the line.
y=3x+b using (x,y)=(1,6).
6=3(1)+b
6=3+b
Subtract 3 on both sides:
3=b
So the equation is y=3x+3
Point-slope form is another form we can put our line into
y-y1=m(x-x1)
where m is the slope and (x1,y1) is a point on the line.
We have m=3 and a point (x1,y1) on the line is (1,6).
y-6=3(x-1)
[tex]\huge{\boxed{y=3x+3}}[/tex]
It could also be [tex]\boxed{y-6=3(x-1)}[/tex]
We can use point-slope to find this. Parallel lines have the same slope, and the given line has a slope of 3 ([tex]m[/tex] in [tex]y=mx+b[/tex]). This means that the parallel line will also have a slope of 3.
Point-slope form is [tex]y-y_1=m(x-x_1)[/tex], where [tex]m[/tex] is the slope and [tex](x_1, y_1)[/tex] is a known point on the line.
Plug in the values. [tex]\boxed{y-6=3(x-1)}[/tex] (point-slope form)
Distribute. [tex]y-6=3x-3[/tex]
Add 6 to both sides. [tex]\boxed{y=3x+3}[/tex] (slope-intercept form)
