Respuesta :
Answer:
For a: The correct answer is [tex]Br^-[/tex]
For b: The correct answer is Radon.
For c: The correct answer is [tex]Se^{2-}[/tex]
For d: The correct answer is [tex]Rb^+[/tex]
For e: The correct answer is [tex]Pb^{2+}[/tex]
Explanation:
An ion is formed when an atom looses or gains electron.
When an atom looses electrons, it will form a positive ion known as cation.
When an atom gains electrons, it will form a negative ion known as anion.
Atomic number is defined as the number of protons or electrons that are present in a neutral atom.
Atomic number = number of protons = number of electrons
Atomic mass is defined as the sum of number of protons and neutrons that are present in an atom.
Atomic mass = Number of protons + Number of neutrons
- For a:
Halogens are Fluorine (Z = 9), Chlorine (Z = 17), Bromine (Z = 35), Iodine (Z = 53) and Astatine (Z = 85)
Bromine is the 35th element of the periodic table having electronic configuration [tex][Ar]3d^{10}4s^24p^5[/tex]
This element will gain 1 electron and will form [tex]Br^-[/tex] ion.
The ion formed has 36 electrons.
- For b:
Noble gas having 86 protons means the element having atomic number 86 is Radon.
Thus, the correct answer is Radon.
- For c:
Group 6A elements are Oxygen (Z = 8), Sulfur (Z = 16), Selenium (Z = 34), Tellurium (Z = 52) and Polonium (Z = 84)
Selenium is the 34th element of the periodic table having electronic configuration [tex][Ar]3d^{10}4s^24p^4[/tex]
This element will gain 2 electrons and will form [tex]Se^{2-}[/tex] ion.
The ion formed has 36 electrons.
- For d:
Alkali metals are Lithium (Z = 3), Sodium (Z = 11), Potassium (Z = 19), Rubidium (Z = 37), Cesium (Z = 55) and Francium (Z = 87)
Rubidium is the 34th element of the periodic table having electronic configuration [tex][Kr]5s^1[/tex]
This element will loose 1 electron and will form [tex]Rb^{+}[/tex] ion.
The ion formed has 36 electrons.
- For e:
Group 4A elements are Carbon (Z = 6), Silicon (Z = 14), Germanium (Z = 32), Tin (Z = 50) and Lead (Z = 82)
Lead is the 82th element of the periodic table having electronic configuration [tex][Xe]4f^{14}5d^{10}6s^26p^2[/tex]
This element will loose 2 electrons and will form [tex]Pb^{2+}[/tex] ion.
The ion formed has 80 electrons.
