Answer : The radius of a barium atom in angstroms is, [tex]2.22\AA[/tex]
Explanation :
The conversion used for radius from meter to angstroms is:
[tex](1m=1\times 10^{10}\AA)[/tex]
As we are given the radius of a barium atom in meter (m) is, [tex]2.22\times 10^{-10}m[/tex]
Now we have to determine the radius of a barium atom in angstrom.
As, [tex]1m=1\times 10^{10}\AA[/tex]
So, [tex]2.22\times 10^{-10}m=\frac{2.22\times 10^{-10}m}{1m}\times (1\times 10^{10}\AA)=2.22\AA[/tex]
Therefore, the radius of a barium atom in angstroms is, [tex]2.22\AA[/tex]
