Respuesta :
Answer:
For a: The volume of bacterial cell in cubic mili meters is [tex]2.56\times 10^{-9}mm^3[/tex]
For b: The volume of 105 cells is [tex]2.668\times 10^{-13}L[/tex]
Explanation:
- For a:
We are given:
Volume of 1 bacterial cell = [tex]2.56\mu m^3[/tex]
To convert it into cubic mili meters, we use the conversion factor:
[tex]1\mu m^3=10^{-9}mm^3[/tex]
Converting the given volume into cubic milimeters, we get:
[tex]\Rightarrow 2.56\mu m^3\times (\frac{10^{-9}mm^3}{1\mu m^3})=2.56\times 10^{-9}mm^3[/tex]
Hence, the volume of bacterial cell in cubic mili meters is [tex]2.56\times 10^{-9}mm^3[/tex]
- For b:
To convert it into liters, we use the conversion factor:
[tex]1\mu m^3=10^{-15}L[/tex]
Converting the given volume into cubic milimeters, we get:
[tex]\Rightarrow 2.56\mu m^3\times (\frac{10^{-15}L}{1\mu m^3})=2.56\times 10^{-15}L[/tex]
This volume is the volume of 1 cell.
To calculate the volume of 105 cells, we apply unitary method:
1 cell occupies a volume of [tex]2.56\times 10^{-15}L[/tex]
So, 105 cells will occupy a volume of [tex]105\times 2.56\times 10^{-15}=2.668\times 10^{-13}L[/tex]
Hence, the volume of 105 cells is [tex]2.668\times 10^{-13}L[/tex]
