Two children are throwing a ball back and forth straight across the back seat of a car. The ball is being thrown 8 mph relative to the car, and the car is travelling 45 mph down the road. If one child doesn't catch the ball, and it flies out the window, in what direction does the ball fly (ignoring wind resistance)?

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aristocles aristocles · Answer 1 · 2019-08-15T07:15:38+02:00

Answer:

ball will move at an angle of 10.1 degree with respect to the motion of car

Explanation:

Velocity of ball relative to the car is 8mph horizontally

now if the car is moving in moving in forward direction with speed 45 mph

then the net speed of the ball is vector sum of both the speed

[tex]v_{bc} = \vec v_b - \vec v_c[/tex]

[tex]\vec v_b = \vec v_{bc} + \vec v_c[/tex]

here we can say that relative speed of the ball with respect to car is in Y direction while car is moving in x direction

so it is given as

[tex]\vec v_b = 8 \hat j + 45 \hat i[/tex]

now we have

[tex]tan\theta = \frac{v_y}{v_x}[/tex]

[tex]tan\theta = \frac{8}{45}[/tex]

[tex]\theta = 10.1^0[/tex]

so ball will move at an angle of 10.1 degree with respect to the motion of car

onyebuchinnaji onyebuchinnaji · Answer 2 · 2022-04-12T14:06:41+02:00

The direction of the ball when it is missed by one child is 10 degrees South of west.

The position of the ball is determined by applying the concept of relative velocity between the ball and the moving car.

vx = 45 mph

vy = 8 mph

The direction of the ball when it flies out is determined as follows;

tanθ = vy/vx

[tex]\theta = tan^{-1} (\frac{v_y}{v_x} )\\\\\theta = tan^{-1} (\frac{8}{45} )\\\\\theta = 10 ^0[/tex]

Thus, the direction of the ball when it is missed by one child is 10 degrees South of west.

Learn more about relative velocity here: https://brainly.com/question/17228388