For this case we have the following equation:
[tex]\frac {4} {3} b + 2 = 4- \frac {1} {3} b[/tex]
Subtracting 2 from both sides we have:
[tex]\frac {4} {3} b = 4- \frac {1} {3} b-2[/tex]
We add similar terms from the right side of the equation:
[tex]\frac {4} {3} b = 2- \frac {1} {3} b[/tex]
Adding[tex]\frac {1} {3}[/tex] b to both sides:
[tex]\frac {4} {3} b + \frac {1} {3} b = 2\\\frac {4 + 1} {3} b = 2\\\frac {5} {3} b = 2[/tex]
Multiplying by 3 on both sides:
[tex]5b = 3 * 2\\5b = 6[/tex]
Dividing between 5 on both sides:
[tex]b = \frac {6} {5}[/tex]
Answer:
[tex]b = \frac {6} {5} = 1.2[/tex]
