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In expansion of (2x+1)(x^2+px+4), the coefficient of x is twice the coefficient of x^2.

Find the value of x​

Respuesta :

You're probably supposed to find the value of p and not x, which is impossible to do.

Expanding gives

[tex](2x+1)(x^2+px+4)=2x^3+(1+2p)x^2+(8+p)x+4[/tex]

We're told that

[tex]8+p=2(1+2p)[/tex]

which we can use to solve for p:

[tex]8+p=2+4p[/tex]

[tex]6=3p[/tex]

[tex]\boxed{p=2}[/tex]