A plant foreman wanted to know how many hours had been spent on a particular project. He asked his supervisors to report the hours worked by each department. Here’s the information he received. Department A. . . . . . . . . . . . . . . . . . . . . . . . . . .202.5 hours
Department B . . . . . . . . . . . . . . . . . . . . . . . . . . 212 3⁄4 hours
Department C . . . . . . . . . . . . . . . . . . . . . . . . . .198.25 hours
Department D. . . . . . . . . . . . . . . . . . . . . . . . . . .215 1⁄5 hours
Calculate the total number of hours spent on this project by all four departments. (Hint: Change all the hours to either decimals or fractions before adding.)

Respuesta :

Answer:

828.7 hours.

Step-by-step explanation:

To answer a question in which the total time has to be calculated of all the activities, first of all, all the times have to be converted to a single form. There are two types: decimals and fractions. Convert the fractions into decimals.

Department A = 202.50 hours.

Department B = 212 3⁄4 hours  = 212.75 hours.

Department C = 198.25 hours.

Department D = 215 1⁄5 hours = 215.20 hours.

Therefore, the total number of hours spent on this project by all four departments. is the sum of all the above numbers. 202.50 hours + 212.75 hours + 198.25 hours + 215.20 hours = 828.7 hours.

Therefore, the total time is 828.7 hours!!!

Answer:

828.7 hours

Step-by-step explanation:

We have the following data:

Department A. . . . . . . . . . . . . . . . . . . . . . . . . . .202.5 hours

Department B . . . . . . . . . . . . . . . . . . . . . . . . . . 212 3⁄4 hours

Department C . . . . . . . . . . . . . . . . . . . . . . . . . .198.25 hours

Department D. . . . . . . . . . . . . . . . . . . . . . . . . . .215 1⁄5 hours

Note that the hours recorded in department B and D are written in the form of a mixed number

Before making the sum we must convert the mixed numbers into decimal form

Then we add the main number with the fraction that accompanies it

[tex]Department\ B = 212\ \frac{3}{4}\ hours =212+\frac{3}{4} = 212.75\ hours\\\\Department\ D=215\ \frac{1}{5}\ hours=215 + \frac{1}{5} = 215.2\ hours[/tex]

Finally the total hours are:

[tex]202.5 + 212.75 + 198.25+215.2=828.7\ hours[/tex]