Answer:
[tex]\sigma = 65.25\ ksi[/tex]
Explanation:
given data:
D = 8 inch
R =4 inch
thickness = 0.018 inch
width = 0.625 inch
[tex]E =29*10^6 psi[/tex]
from bending equation we know that
[tex]\frac{\sigma}{y} = \frac{M}{I} = \frac{E}{R}[/tex]
[tex]\sigma = \frac{Ey}{R}[/tex]
Where y represent distance from neutral axis
[tex]y = \frac{t}[2}[/tex]
[tex]y = \frac{0.018}{2}[/tex]
y = 0.009inch
[tex]\sigma = \frac{29*10^6*0.009}{4}[/tex]
[tex]\sigma = 65250\ psi[/tex]
[tex]\sigma = 65.25\ ksi[/tex]
