Answer:
The weight required on the piston equals 420 Newtons.
Explanation:
from the principle of transmission of pressure in a hydraulic lift we have
[tex]\frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{1}}[/tex]
where
'F' is the force that acts on the piston
'A' is the area of the piston.
Since the force in the question is 21000 Newtons thus upon putting the values in the above equation we get
[tex]\frac{21000}{3.0m^{2}}=\frac{W}{0.06m^{2}}[/tex]
Solving for [tex]W[/tex] we get
[tex]W=\frac{21000}{3}\times 0.06\\\\\therefore W=420Newtons[/tex]
