A slight breeze is blowing over the hot tub above and yields a heat transfer coefficient h of 20 W/m2 -K. The air temperature is 75 F. If the surface area of the hot tub is 7.5 m2 , what is the heat loss (heat rate) due to convection? The temp of Hot Tube is 102F.

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nuuk nuuk · Answer 1 · 2019-09-19T08:15:13+02:00

Answer:4050 W

Explanation:

Given

Heat transfer Coefficient(h)=[tex]20 W/m^2-K[/tex]

Air temperature =75 F

surface area(A)=[tex]7.5 m^2[/tex]

Temperature of hot tube is 102 F

We know heat transfer due to convection is given by

[tex]Q=hA\left ( \Delta T\right )[/tex]

[tex]Q=20\times 7.5\left ( 102-75\right )=4050 W[/tex]

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