Answer:
The image height is 0.00283 m or 0.283 cm and is inverted due to the negative sign
Explanation:
u = Object distance = 9 m
v = Image distance = 1.7 cm (as the image is forming on the retina)
[tex]h_u[/tex]= Object height = 1.5 m
Magnification
[tex]m=-\frac{v}{u}=\frac{h_v}{h_u}\\\Rightarrow -\frac{v}{u}=\frac{h_v}{h_u}\\\Rightarrow -\frac{0.017}{9}=\frac{h_v}{1.5}\\\Rightarrow h_v=-0.00283\ m[/tex]
The image height is 0.00283 m or 0.283 cm and is inverted due to the negative sign
