Answer:
-7.95 pC
Explanation:
If the particle experiences an attractive force towards a positive charge it must be negatively charged.
Coulomb's law:
[tex]F = \frac{1}{4 \pi * \epsilon 0} \frac{q1 * q2}{d^2}[/tex]
[tex]q2 = \frac{4 \pi * \epsilon 0 * F * d^2}{q1}[/tex]
With ε0 = 8.85*10^-12 C^2/(N*m^2)
Then:
[tex]q2 = \frac{4 \pi * 8.85*10^-12 * (-4.1) * 0.24^2}{3.3} = -7.95*10^-12 C = -7.95 pC[/tex]
