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Find the work done "by" the electric field on a negatively charged point particle with a charge of 7.7 x 10^-6 C as it is moved from a potential of 15.0 V to one of 5.0 V. (Include the sign of the value in your answer.)

Respuesta :

Answer:

77 x 10⁻⁶ J

Explanation:

Work done by electric field

= charge x potential difference

= 7.7 x 10⁻⁶ x ( 15 - 5)

= 77 x 10⁻⁶ J

work done will be positive because direction of force and displacement are same.

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