Answer:
The charge transferred equals [tex]-4.96\times 10^{-6}Columbs[/tex]
Explanation:
The charge quantizatrion principle states that the charge is always transferred in terms of product of fundamental charges.
Mathematically [tex]Q=ne[/tex]
where
'e' is the fundamental magnitude of charge
Thus charge transferred by [tex]4.4\times 10^{13}[/tex] electrons equals
[tex]Q_{1}=4.4\times 10^{13}\times -1.6\times 10^{-19}=-7.04\times 10^{-6}Columbs[/tex]
Similarly charge transferred by [tex]1.3\times 10^{13}[/tex] protons equals
[tex]Q_{2}=1.3\times 10^{13}\times 1.6\times 10^{-19}=2.08\times 10^{-6}Columbs[/tex]
Thus the net charge transferred equals
[tex]Q_{1}+Q_{2}=-7.04\times 10^{-6}+2.08\times 10^{-6}\\\\=-4.96\times 10^{-6}columbs[/tex]
