Answer:
The time is 5.71 sec.
Explanation:
Given that,
Acceleration [tex]a= -4.20 m/s^2[/tex]
Initial velocity = 24.0 m/s
We need to calculate the time
Using equation of motion
v = u+at[/tex]
Where, v = final velocity
u = inital velocity
t = time
a = acceleration
Put the value into the formula
[tex]0 =24.0 +(-4.20)\times t[/tex]
[tex]t = \dfrac{-24.0}{-4.20}[/tex]
[tex]t=5.71\ sec[/tex]
Hence, The time is 5.71 sec.
