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At time t=0, rock A is dropped from rest from a height of 90 m. At the same instant, rock B is launched straight up from the ground level with an initial speed of 30 m/s. Write an equation of motion for rock A and B, giving its position at all time.

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jorgezarate

Answer:

rock A: [tex]y=90-1/2*g*t^2[/tex]

rock B: [tex]y=30*t-1/2*g*t^2[/tex]

g=9.81m/s^2

Explanation:

Kinematics equation:

[tex]y=y_{o}+v_{oy}*t+1/2*a*t^2[/tex]

in our case the acceleration is the gravity and it has a negative direction.

a=-g

rock A, yo=90m, Voy=0m/s:

[tex]y=90-1/2*g*t^2[/tex]

rock B, yo=0m, Voy=30m/s:

[tex]y=30*t-1/2*g*t^2[/tex]

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