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While ice skating, you unintentionally crash into a person. Your mass is 60kg
and you are traveling east at 8.0m/s
with respect to the ice. The mass of the other person is 80kg
and he is traveling north at 9.0m/s
with respect to the ice. You hang on to each other after the collision. In what direction and at what speed are you traveling just after the collision?

Respuesta :

krlosdark12

Answer:

The speed is 6.1m/s with an angle of 56.3 degrees north of east.

Explanation:

We meed to apply the Linear momentum theorem:

[tex]m1*vo1+m2*vo2=m1*vf1+m2*vf2\\60*(8.0m/s(East))+80*(9.0m/s(North))=140*vf\\vf=3.4m/s(East)+5.1m/s(North)[/tex]

The magnitude of the velocity is given by:

[tex]v=\sqrt{Veast^2+Vnorth^2} \\v=6.1m/s[/tex]

and the angle:

[tex]\alpha =arctg(\frac{Vnorth}{Veast})\\\alpha=56.3^o[/tex]

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