ANSWER:
The toys with Fanny and Simon is 432.
SOLUTION:
Let, the number of toys with fanny be x and number of toys with Simon be y.
Given that, Fanny had 5 times as many toys as Simon.
Then, x = 5y ---- (1)
And after their aunt gave each of them 108 toys, Fanny had twice as many toys as Simon.
x + 108 = 2(y + 108)
x + 108 = 2y + 216
x – 2y = 216 – 108
x – 2y = 108 ---- (2)
Now substitute the (1) in (2)
5y – 2y = 108
3y = 108
y = 36
Again substitute y value in (1)
x = [tex]5 \times 36[/tex]
x = 180
Now, total toys with them = (x + 108) + (y + 108)
= (180 + 108) + (36 + 108) = 432
Hence, the toys with fanny and simon is 432.
