Answer:
[tex]\Delta t=2s[/tex]
Explanation:
Power is by definition energy per unit time P=E/t, so the time it takes to provide an energy E at power P is t=E/P. We have the energy (E=8.5\times10^5J) and both powers, ([tex]P_1[/tex]=170hp and [tex]P_2[/tex]=130hp, 40hp less than [tex]P_1[/tex]), which for converting to Watts we only need to multiply the power in hp by the conversion factor 745.7W/hp.
We can then calculate the difference between the times asked:
[tex]\Delta t=t_2-t_1=\frac{E}{P_2}-\frac{E}{P_1}=E( \frac{1}{P_2}-\frac{1}{P_1})[/tex]
Which for our values means:
[tex]\Delta t=E(\frac{1}{P_2}-\frac{1}{P_1})=(8.5\times10^{5}J)(\frac{1}{(130hp)(745.5W/hp)}-\frac{1}{(170hp)(745.5W/hp)})=2s[/tex]