Respuesta :
Answer: 405.3 minutes
Explanation: In order to explain this problem we have to use the following:
Fisrtly we calculate the volume of the wire, this is given by:
Vwire=π*r^2*L where r and L are the radius and L the length of teh wire, respectively.
Vwire=π*1.25*10^-3*0.26=1.27*10^-6 m^3
then the number of the total electrons in tthe wire volume is given by;
n° electrons in the wire=ρ*Vwire=8.4*10^28*1.27*10^-6 m^3=1.07 *10^23
Finally, considering the current in the wire equal to 4.4*10^18 electrons/s
the time consuming to extract all the electrons from the wire is given by:
t= total electrons in the wire/ current=1.067*10^23/4.4*10^18=24,318 s
equivalent to 405.3 minutes
A rate of electric charge flowing past a place or region is called an electric current.It take 405.3 minute for a single electron in the electron sea to drift from one end to the other end.
What is electric current ?
A rate of electric charge flowing past a place or region is called an electric current. A net passage of electric charge through a region creates an electric current.
Charge carriers are the moving particles and different conductors may include different types of charge carriers. Electrons travelling through a wire serve as charge carriers in electric circuits.
The given data in the problem will be
[tex]\partial[/tex] is the density of electrons=8.4×10²⁸ kg/m³
i is the eletric current =4.4×10¹⁸ electrons/sec
d is the diameter of the wire =2.5 mm=2.5
l is the length of wire = 26 cm
v is The volume of the wire
[tex]\rm v=\pi r^{2} l\\\\\rm v=3.14\tims (1.25)^{2} 0.26\\\\\rm v=1.257\times10^{-6}[/tex] m³
the no of total electrons can be find by
no of electrons= density × volume
[tex]\RM{n=\partial \times V}[/tex]
[tex]\rm{n=\partial \times V}\\\\\rm{n=8.4\times10^{28}}\times1.257\times10^{-6}\\\\\rm n=1.07\times10^{23}[/tex]
Time required for the drifting electron is equal to the ratio of no of electrons to the electric current flows.
[tex]\rm t= \frac{n}{I}\\\\ \rm t= \frac{1.07\times 10^23}{4.4\times10^{28}} \\\\\rm t=405.3 minute.[/tex]
Hence It take 405.3 minute for a single electron in the electron sea to drift from one end to the other end.
To learn more about the electric current refer to the link;
https://brainly.com/question/3029193
