Answer:
The value of x in the given equation is 0.
Solution:
We know that any number with power 0 is 1 [tex](a^{0}=1)[/tex]
As given,
[tex]\left(7^{2}\right)^{x}=1[/tex]
As per the formula, [tex](a^{m})^n = a^{m+n}[/tex]
Here a is 7; 2 is m and x is n.
On substituting the values,
[tex](7)^{2\times x}=1[/tex]
[tex](7)^{2\times x}=7^{0}[/tex] (//any power of 0 is 1)
Hence from both the side we get,
[tex](2\times x) = 0[/tex]
So, x = 0.
