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Boxes are transported from one location to another in a warehouse by means of a conveyor belt that moves with a constant speed of 0.56 m/s. At a certain location the conveyor belt moves for 2.0 m up an incline that makes an angle of 15° with the horizontal. Assume that a 2.1 kg box rides on the belt without slipping. At what rate is the force of the conveyor belt doing work on the box as the box moves up the 15° incline?

Respuesta :

Answer:

P = 15.90 W

Explanation:

given,

speed of conveyor belt = 0.56 m/s

conveyor belt move up to = 2 m      

angle made with the horizontal = 15°

mass of the box = 2.1 kg                      

rate is the force of the conveyor belt doing work on the box as the box moves up                                                  

P = F v cos ∅

P = 3 × 9.8 × 0.56 × cos 15°

P = 15.90 W

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