AJ takes a stroll to the pizza place for lunch. He walks 2 km east, then 1 km south and then 2 km east!
again. That's a long way to walk for pizza, but he thought it was worth it. What was the magnitude of
his total displacement, in km?

The displacement is a vector connecting the final position with the initial position - so the magnitude of the displacement is the distance in a straight line between the final position and the initial position.

The list of movements made by AJ is:

2 km east

1 km south

2 km east

Adding the displacements in the same direction, its net displacement is

(2+2) km east + 1 km south =

4 km east + 1 km south

The two vectors are perpendicular to each other, so we can find the resultant (which is the magnitude of the displacement) by using Pythagorean's theorem:

[tex]d=\sqrt{4^2+1^2}=\sqrt{17}=4.12 km[/tex]

AJ takes a stroll to the pizza place for lunch. He walks 2 km east, then 1 km south and then 2 km east! again. That's a long way to walk for pizza, but he thought it was worth it. What was the magnitude of his total displacement, in km?

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AJ takes a stroll to the pizza place for lunch. He walks 2 km east, then 1 km south and then 2 km east!
again. That's a long way to walk for pizza, but he thought it was worth it. What was the magnitude of
his total displacement, in km?