The equation of the line that contains the given segment is y= -5x + 21
Step-by-step explanation:
Here you are required to find the equation of a line segment AB where point A is (3,6) and point B is (4,1).
First find the slope of the line.
slope ,m = Δy/Δx
Δy=1-6 = -5
Δx=4-3=1
m=-5/1 = -5
Taking one point (4,1) and another one on the line segment (x,y) with a slope of -5, the equation can be written as;
-5 =Δy/Δx
-5= y-1/x-4
y-1=-5(x-4)
y-1=-5x+20
y= -5x +20 + 1
y= -5x + 21
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Keywords: line segment, equation
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