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contestada

A runner accelerates to 8 m/s in the first 2 s out of the starting block. What is
the runner's rate of acceleration?

Respuesta :

Answer: [tex]4 m/s^{2}[/tex]

Explanation:

In this situation the following equation will be useful:

[tex]V=V_{o}+at[/tex]

Where:

[tex]V=8 m/s[/tex] is the runner’s final velocity  

[tex]V_{o}=0 m/s[/tex] is the runner’s initial velocity  (assuming it started from rest)

[tex]a[/tex] is the runner's acceleration

[tex]t=2 s[/tex] is the time

Finding [tex]a[/tex]:

[tex]a=\frac{V}{t}[/tex]

[tex]a=\frac{8 m/s}{2 s}[/tex]

[tex]a=4 m/s^{2}[/tex]