Please, help.. (: P)

Answer:
[tex]y=-\frac{3}{5} +1.4[/tex]
Explanation:
[tex]y+1=-\frac{3}{5} (x-4)[/tex]
> What you do to one side, you do to the other. So subtract 1 from both sides to get y by itself to get it into the slope intercept formula: [tex]y=mx+b[/tex]
> Then distribute (multiply) the [tex]-\frac{3}{5}[/tex] to x and -4 to get [tex]-\frac{3}{5} x+2.4[/tex]
> Your new equation is [tex]y=-\frac{3}{5} +2.4-1[/tex]
> 2.4 and 1 are like terms so subtract 1 from 2.4 to get 1.4 which is the point that you plot on the graph.
> Since [tex]\frac{3}{5}[/tex] is negative, your line will go up 3 and down 5 using the [tex]\frac{rise}{run}[/tex] formula. Rise is vertical (y) and Run is horizontal (x).
Answer:
The given equation is
[tex]y+1=-\frac{3}{5} (x+4)[/tex]
The graph of this equation is line, because it's a linear equation.
First, we rewrite the given equation into a slope-intercept form
[tex]y+1=-\frac{3}{5} (x+4)\\y=-\frac{3}{5}x-\frac{12}{5}-1\\ y=-\frac{3}{5}x-\frac{17}{5}[/tex]
Now, for [tex]x=0[/tex] we find [tex]y[/tex]
[tex]y=-\frac{3}{5}(0)-\frac{17}{5}=-\frac{17}{5}[/tex]
Then, for [tex]y=0[/tex] we find [tex]x[/tex]
[tex]0=-\frac{3}{5}x-\frac{17}{5}\\\frac{17}{5}=-\frac{3}{5}x\\x=-\frac{17}{3}[/tex]
So, the two points that we use to graph are [tex](0,-\frac{17}{5})[/tex] and [tex](-\frac{17}{3},0)[/tex].
The graph is attached.