Pressure of the ideal gas=505.7kPa
Given:
No of moles=0.907mole
Temperature of the gas=[tex]12^{\circ} \mathrm{C}[/tex]
Volume of the gas=4.25L
To find:
Pressure of the gas
Step by Step Explanation:
Solution:
According to the ideal gas equation
[tex]P V=n R T[/tex] and from this pressure is derived as
[tex]P=\frac{n R T}{V}[/tex]
Where P=Pressure of the gas
V=Volume of the gas=4.25L
n=No of the moles=0.907mole
R=Gas constant=8.314[tex]J / m o l^{-1} K^{-1}[/tex]
T=Temperature of the gas=[tex]12^{\circ} \mathrm{C}[/tex] =273+12=285K
Substitute these known values in the above equation we get
[tex]P=\frac{0.907 \times 8.314 \times 285}{4.25}[/tex]
[tex]P=\frac{2149.13}{4.25}[/tex]
P=505.7kPa
Result:
Thus the pressure of the ideal gas is 505.7kPa
