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The amount of enzyme activity in a cell that is homozygous for a mutant allele is 400 units. The amount of enzyme activity in a cell homozygous for the WT allele is 200 units. The amount of enzyme activity in a heterozygote is 300 units. What is the dominance relationship between the WT and mutant allele for the phenotype of amount of enzyme per cell?

Respuesta :

Answer:

WT and mutant  allele show that incomplete dominance

Explanation:

given data

homozygous for a mutant allele = 400 units

WT allele = 200 units

heterozygote = 300

to find out

dominance relationship between the WT and mutant allele

solution

we know that Enzyme activity homozygous mutant = 400 unit and

WT =   200 unit

so each WT allele contributes 100 units

and Heterozygous =300 units

that is intermediate between Homozygous WT and homozygous Recessive

and WT and mutant alleles are incompletely dominant

and phenotype of heterozygote is the intermediate of both homozygous WT and the homozygous mutant

so WT and mutant  allele show that incomplete dominance

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